What are the solutions to the equation 9=pir^216 ?

The solutions to the equation 9=pir^216 are r= 3/(4sqrt(pi)),r=-3/(4sqrt(pi))

Find the zeros of 9=pir^216

The zeros of 9=pir^216 are r= 3/(4sqrt(pi)),r=-3/(4sqrt(pi))

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9 = π r^{2} 16

r = \frac{3}{4 π}, r = - \frac{3}{4 π}

Solution steps

9 = π r^{2} \cdot 16

Switch sides

π r^{2} \cdot 16 = 9

Divide both sides by

π 16

r^{2} = \frac{9}{π 16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{9}{π 16}, r = - \frac{9}{π 16}

\frac{9}{π 16} = \frac{3}{4 π}

- \frac{9}{π 16} = - \frac{3}{4 π}

r = \frac{3}{4 π}, r = - \frac{3}{4 π}

a = 2 4^{2} + 2 0^{2}

\frac{2 ^{2}}{2 ^{- 2}}

1 < 4 x + 5 < 17

x \cdot 2 x

What are the solutions to the equation 9=pir^216 ?
The solutions to the equation 9=pir^216 are r= 3/(4sqrt(pi)),r=-3/(4sqrt(pi))
Find the zeros of 9=pir^216
The zeros of 9=pir^216 are r= 3/(4sqrt(pi)),r=-3/(4sqrt(pi))