What is (s^{2/5}t^{1/3})(s^{1/2}t^{1/2}) ?

The solution to (s^{2/5}t^{1/3})(s^{1/2}t^{1/2}) is s^{9/10}t^{5/6}

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simplify (s^{2/5}t^{1/3})(s^{1/2}t^{1/2})

simplify

(s^{\frac{2}{5}} t^{\frac{1}{3}}) (s^{\frac{1}{2}} t^{\frac{1}{2}})

s^{\frac{9}{10}} t^{\frac{5}{6}}

Solution steps

(s^{\frac{2}{5}} t^{\frac{1}{3}}) (s^{\frac{1}{2}} t^{\frac{1}{2}})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

s^{\frac{2}{5}} s^{\frac{1}{2}} = s^{\frac{2}{5} + \frac{1}{2}}

= t^{\frac{1}{3}} s^{\frac{2}{5} + \frac{1}{2}} t^{\frac{1}{2}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

t^{\frac{1}{3}} t^{\frac{1}{2}} = t^{\frac{1}{3} + \frac{1}{2}}

= s^{\frac{2}{5} + \frac{1}{2}} t^{\frac{1}{3} + \frac{1}{2}}

s^{\frac{2}{5} + \frac{1}{2}} = s^{\frac{9}{10}}

= s^{\frac{9}{10}} t^{\frac{1}{3} + \frac{1}{2}}

t^{\frac{1}{3} + \frac{1}{2}} = t^{\frac{5}{6}}

= s^{\frac{9}{10}} t^{\frac{5}{6}}

ln (1.9)

\frac{2}{- 1 - 2}

\frac{2 x + 6}{5} = 4 x - 3

4 x^{2} - 100 x - 1000 \geq 0

4 y^{2} - 11 y + 6

What is (s^{2/5}t^{1/3})(s^{1/2}t^{1/2}) ?
The solution to (s^{2/5}t^{1/3})(s^{1/2}t^{1/2}) is s^{9/10}t^{5/6}