What are the solutions to the equation 9p^2=-10p+1 ?

The solutions to the equation 9p^2=-10p+1 are p=(-5+sqrt(34))/9 ,p=-(5+sqrt(34))/9

Find the zeros of 9p^2=-10p+1

The zeros of 9p^2=-10p+1 are p=(-5+sqrt(34))/9 ,p=-(5+sqrt(34))/9

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9 p^{2} = - 10 p + 1

p = \frac{- 5 + 34}{9}, p = - \frac{5 + 34}{9}

Decimal Notation

p = 0.09232 \dots, p = - 1.20343 \dots

Solution steps

9 p^{2} = - 10 p + 1

Move

1

to the left side

9 p^{2} - 1 = - 10 p

Move

10 p

to the left side

9 p^{2} - 1 + 10 p = 0

Write in the standard form

a x^{2} + b x + c = 0

9 p^{2} + 10 p - 1 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 9 ( - 1 )}{2 \cdot 9}

1 0^{2} - 4 \cdot 9 (- 1) = 234

p_{1, 2} = \frac{- 10 \pm 2 34}{2 \cdot 9}

Separate the solutions

p_{1} = \frac{- 10 + 2 34}{2 \cdot 9}, p_{2} = \frac{- 10 - 2 34}{2 \cdot 9}

p = \frac{- 10 + 2 34}{2 \cdot 9} : \frac{- 5 + 34}{9}

p = \frac{- 10 - 2 34}{2 \cdot 9} : - \frac{5 + 34}{9}

The solutions to the quadratic equation are:

p = \frac{- 5 + 34}{9}, p = - \frac{5 + 34}{9}

7 x = 0

10 x^{4} (8 x y)

x^{3} - 3 x^{2} - 16 x - 12

24 x y - 192 x - 42 y^{2} + 336 y

x^{4} - 11 x^{2} + 30

What are the solutions to the equation 9p^2=-10p+1 ?
The solutions to the equation 9p^2=-10p+1 are p=(-5+sqrt(34))/9 ,p=-(5+sqrt(34))/9
Find the zeros of 9p^2=-10p+1
The zeros of 9p^2=-10p+1 are p=(-5+sqrt(34))/9 ,p=-(5+sqrt(34))/9