What are the solutions to the equation x^2-2x+12=0 ?

The solutions to the equation x^2-2x+12=0 are x=1+sqrt(11)i,x=1-sqrt(11)i

Find the zeros of x^2-2x+12=0

The zeros of x^2-2x+12=0 are x=1+sqrt(11)i,x=1-sqrt(11)i

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x^{2} - 2 x + 12 = 0

x = 1 + 11 i, x = 1 - 11 i

Solution steps

x^{2} - 2 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 12 : 211 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 11 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 11 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 11 i}{2 \cdot 1} : 1 + 11 i

x = \frac{- ( - 2 ) - 2 11 i}{2 \cdot 1} : 1 - 11 i

The solutions to the quadratic equation are:

x = 1 + 11 i, x = 1 - 11 i

9 a^{2} - 36 a + 32

\frac{33 !}{6 ! ( 33 - 6 ) !}

2 (x + 2)^{2} = 24

\frac{- x + 2}{2} - \frac{7 - 7 x}{8} < - 7

\frac{d}{11} + 3 d = 4 (d - 5)

What are the solutions to the equation x^2-2x+12=0 ?
The solutions to the equation x^2-2x+12=0 are x=1+sqrt(11)i,x=1-sqrt(11)i
Find the zeros of x^2-2x+12=0
The zeros of x^2-2x+12=0 are x=1+sqrt(11)i,x=1-sqrt(11)i