What are the solutions to the equation 1/2 x^2-x+5=0 ?

The solutions to the equation 1/2 x^2-x+5=0 are x=1+3i,x=1-3i

Find the zeros of 1/2 x^2-x+5=0

The zeros of 1/2 x^2-x+5=0 are x=1+3i,x=1-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{2} x^{2} - x + 5 = 0

x = 1 + 3 i, x = 1 - 3 i

Solution steps

\frac{1}{2} x^{2} - x + 5 = 0

Multiply both sides by

2

x^{2} - 2 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 10 : 6 i

x_{1, 2} = \frac{- ( - 2 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 6 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 6 i}{2 \cdot 1} : 1 + 3 i

x = \frac{- ( - 2 ) - 6 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

x = 1 + 3 i, x = 1 - 3 i

2 x^{2} + 8 x - 10

x^{2} - 9 x + 10 = 0

6 x + 7 = \frac{4 x + 8}{5}

lo g_{3} (\frac{1}{9}) = y

- 4 ∣ 5 x ∣ = 40

What are the solutions to the equation 1/2 x^2-x+5=0 ?
The solutions to the equation 1/2 x^2-x+5=0 are x=1+3i,x=1-3i
Find the zeros of 1/2 x^2-x+5=0
The zeros of 1/2 x^2-x+5=0 are x=1+3i,x=1-3i