What is factor 3u^3+7u^2+6u+14 ?

The solution to factor 3u^3+7u^2+6u+14 is (3u+7)(u^2+2)

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factor 3u^3+7u^2+6u+14

factor

3 u^{3} + 7 u^{2} + 6 u + 14

(3 u + 7) (u^{2} + 2)

Solution steps

3 u^{3} + 7 u^{2} + 6 u + 14

= (3 u^{3} + 7 u^{2}) + (6 u + 14)

Factor out

u^{2}

from

3 u^{3} + 7 u^{2} : u^{2} (3 u + 7)

Factor out

2

from

6 u + 14 : 2 (3 u + 7)

= u^{2} (3 u + 7) + 2 (3 u + 7)

Factor out common term

3 u + 7

= (3 u + 7) (u^{2} + 2)

\frac{21}{15}

\frac{1}{1 - x} > 1 - 2 x

x^{2} - 5 x - 66 = 0

109 = \frac{( 9 \cdot 1 0 ^{9} ) \cdot q}{( 6.38 \cdot 1 0 ^{6} ) ^{2}}

16.1

What is factor 3u^3+7u^2+6u+14 ?
The solution to factor 3u^3+7u^2+6u+14 is (3u+7)(u^2+2)