What are the solutions to the equation (k+2)^2=16 ?

The solutions to the equation (k+2)^2=16 are k=2,k=-6

Find the zeros of (k+2)^2=16

The zeros of (k+2)^2=16 are k=2,k=-6

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(k + 2)^{2} = 16

k = 2, k = - 6

Solution steps

(k + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

k + 2 = 16 : k = 2

Solve

k + 2 = - 16 : k = - 6

The solutions to the quadratic equation are:

k = 2, k = - 6

- \frac{3}{2} + 2

2 x^{4} y x \cdot 6 x y^{2} z^{3}

- 5 (2)^{2}

∣ x ∣ + 7 = 18

What are the solutions to the equation (k+2)^2=16 ?
The solutions to the equation (k+2)^2=16 are k=2,k=-6
Find the zeros of (k+2)^2=16
The zeros of (k+2)^2=16 are k=2,k=-6