What are the solutions to the equation 3/7 y^2+1/7 y= 4/7 ?

The solutions to the equation 3/7 y^2+1/7 y= 4/7 are y=1,y=-4/3

Find the zeros of 3/7 y^2+1/7 y= 4/7

The zeros of 3/7 y^2+1/7 y= 4/7 are y=1,y=-4/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{3}{7} y^{2} + \frac{1}{7} y = \frac{4}{7}

y = 1, y = - \frac{4}{3}

Decimal Notation

y = 1, y = - 1.33333 \dots

Solution steps

\frac{3}{7} y^{2} + \frac{1}{7} y = \frac{4}{7}

Multiply both sides by

7

3 y^{2} + y = 4

Move

4

to the left side

3 y^{2} + y - 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 4) = 7

y_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 1 + 7}{2 \cdot 3}, y_{2} = \frac{- 1 - 7}{2 \cdot 3}

y = \frac{- 1 + 7}{2 \cdot 3} : 1

y = \frac{- 1 - 7}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

y = 1, y = - \frac{4}{3}

x^{6} + 2 x^{4} - 16 x^{2} - 32

4 a^{2} - 8 ab

- 2 x^{3} - 6 x^{2} + 56

ln (1.2)

(3 - i)^{3}

What are the solutions to the equation 3/7 y^2+1/7 y= 4/7 ?
The solutions to the equation 3/7 y^2+1/7 y= 4/7 are y=1,y=-4/3
Find the zeros of 3/7 y^2+1/7 y= 4/7
The zeros of 3/7 y^2+1/7 y= 4/7 are y=1,y=-4/3