What are the solutions to the equation 3p^2+4p=10 ?

The solutions to the equation 3p^2+4p=10 are p=(-2+sqrt(34))/3 ,p=-(2+sqrt(34))/3

Find the zeros of 3p^2+4p=10

The zeros of 3p^2+4p=10 are p=(-2+sqrt(34))/3 ,p=-(2+sqrt(34))/3

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3 p^{2} + 4 p = 10

p = \frac{- 2 + 34}{3}, p = - \frac{2 + 34}{3}

Decimal Notation

p = 1.27698 \dots, p = - 2.61031 \dots

Solution steps

3 p^{2} + 4 p = 10

Move

10

to the left side

3 p^{2} + 4 p - 10 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 10) = 234

p_{1, 2} = \frac{- 4 \pm 2 34}{2 \cdot 3}

Separate the solutions

p_{1} = \frac{- 4 + 2 34}{2 \cdot 3}, p_{2} = \frac{- 4 - 2 34}{2 \cdot 3}

p = \frac{- 4 + 2 34}{2 \cdot 3} : \frac{- 2 + 34}{3}

p = \frac{- 4 - 2 34}{2 \cdot 3} : - \frac{2 + 34}{3}

The solutions to the quadratic equation are:

p = \frac{- 2 + 34}{3}, p = - \frac{2 + 34}{3}

i^{537}

(\frac{8 x ^{2}}{2 x ^{2}})^{2}

3 v^{2} - 84 = 0

ln ∣ x - 1 ∣ = ln (2 x - 1)

- 4 (3 + 5 x) = - 92

What are the solutions to the equation 3p^2+4p=10 ?
The solutions to the equation 3p^2+4p=10 are p=(-2+sqrt(34))/3 ,p=-(2+sqrt(34))/3
Find the zeros of 3p^2+4p=10
The zeros of 3p^2+4p=10 are p=(-2+sqrt(34))/3 ,p=-(2+sqrt(34))/3