What are the solutions to the equation x^2-7x-30=0 ?

The solutions to the equation x^2-7x-30=0 are x=10,x=-3

Find the zeros of x^2-7x-30=0

The zeros of x^2-7x-30=0 are x=10,x=-3

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x^{2} - 7 x - 30 = 0

x = 10, x = - 3

Solution steps

x^{2} - 7 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 30) = 13

x_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 1}

x = \frac{- ( - 7 ) + 13}{2 \cdot 1} : 10

x = \frac{- ( - 7 ) - 13}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 10, x = - 3

\frac{j ^{2} + 7 j + 6}{12 j ^{3} - 14 j ^{2} - 10 j}

1 - \frac{1}{7}

x^{2} - 8 x y - 33 y^{2}

- 2 (18 - 3 y) = 7 y + 2 y

5 x^{2} + 4 x + 1 = 0

What are the solutions to the equation x^2-7x-30=0 ?
The solutions to the equation x^2-7x-30=0 are x=10,x=-3
Find the zeros of x^2-7x-30=0
The zeros of x^2-7x-30=0 are x=10,x=-3