What are the solutions to the equation x^2-18x+81=0 ?

The solutions to the equation x^2-18x+81=0 are x=9

Find the zeros of x^2-18x+81=0

The zeros of x^2-18x+81=0 are x=9

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x^{2} - 18 x + 81 = 0

x = 9

Solution steps

x^{2} - 18 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 81 = 0

x_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 18 )}{2 \cdot 1}

\frac{- ( - 18 )}{2 \cdot 1} = 9

x = 9

The solution to the quadratic equation is:

x = 9

x^{2} - 15 x + 50 < 0

(55 - 2) (5 - 1)

5 x + 3 = 17

(x + 5) (x - 1) = 8 x

6 x^{2} + 5 x - 4 \leq 0

What are the solutions to the equation x^2-18x+81=0 ?
The solutions to the equation x^2-18x+81=0 are x=9
Find the zeros of x^2-18x+81=0
The zeros of x^2-18x+81=0 are x=9