What are the solutions to the equation 64+60x-4x^2=0 ?

The solutions to the equation 64+60x-4x^2=0 are x=-1,x=16

Find the zeros of 64+60x-4x^2=0

The zeros of 64+60x-4x^2=0 are x=-1,x=16

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64 + 60 x - 4 x^{2} = 0

x = - 1, x = 16

Solution steps

64 + 60 x - 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 60 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 ( - 4 ) \cdot 64}{2 ( - 4 )}

6 0^{2} - 4 (- 4) \cdot 64 = 68

x_{1, 2} = \frac{- 60 \pm 68}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 60 + 68}{2 ( - 4 )}, x_{2} = \frac{- 60 - 68}{2 ( - 4 )}

x = \frac{- 60 + 68}{2 ( - 4 )} : - 1

x = \frac{- 60 - 68}{2 ( - 4 )} : 16

The solutions to the quadratic equation are:

x = - 1, x = 16

lo g_{3} (243) = 2 x + 1

3 (3 k - 10) + 1 = 8 (\frac{3}{2} k + 2)

3 m (m + 5) + 4 (m + 5)

12 w^{3} t^{2} - 9 wt + 15 w^{2} t^{3}

(x - 4) \leq 0

What are the solutions to the equation 64+60x-4x^2=0 ?
The solutions to the equation 64+60x-4x^2=0 are x=-1,x=16
Find the zeros of 64+60x-4x^2=0
The zeros of 64+60x-4x^2=0 are x=-1,x=16