What are the solutions to the equation 4x^2+13x+3=0 ?

The solutions to the equation 4x^2+13x+3=0 are x=-1/4 ,x=-3

Find the zeros of 4x^2+13x+3=0

The zeros of 4x^2+13x+3=0 are x=-1/4 ,x=-3

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4 x^{2} + 13 x + 3 = 0

x = - \frac{1}{4}, x = - 3

Decimal Notation

x = - 0.25, x = - 3

Solution steps

4 x^{2} + 13 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

1 3^{2} - 4 \cdot 4 \cdot 3 = 11

x_{1, 2} = \frac{- 13 \pm 11}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 13 + 11}{2 \cdot 4}, x_{2} = \frac{- 13 - 11}{2 \cdot 4}

x = \frac{- 13 + 11}{2 \cdot 4} : - \frac{1}{4}

x = \frac{- 13 - 11}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - 3

\frac{3 + 2 i}{1 - i}

3 - (- 3)^{4}

x^{4} + 2 x^{2} - 35

9 + 5 d - 4 = 25

\frac{5 !}{2 ! 3 !}

What are the solutions to the equation 4x^2+13x+3=0 ?
The solutions to the equation 4x^2+13x+3=0 are x=-1/4 ,x=-3
Find the zeros of 4x^2+13x+3=0
The zeros of 4x^2+13x+3=0 are x=-1/4 ,x=-3