What are the solutions to the equation -5x^2-3x-4x=-2 ?

The solutions to the equation -5x^2-3x-4x=-2 are x=-(7+sqrt(89))/(10),x=(sqrt(89)-7)/(10)

Find the zeros of -5x^2-3x-4x=-2

The zeros of -5x^2-3x-4x=-2 are x=-(7+sqrt(89))/(10),x=(sqrt(89)-7)/(10)

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- 5 x^{2} - 3 x - 4 x = - 2

x = - \frac{7 + 89}{10}, x = \frac{89 - 7}{10}

Decimal Notation

x = - 1.64339 \dots, x = 0.24339 \dots

Solution steps

- 5 x^{2} - 3 x - 4 x = - 2

Refine

- 5 x^{2} - 7 x = - 2

Move

2

to the left side

- 5 x^{2} - 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 5 ) \cdot 2}{2 ( - 5 )}

(- 7)^{2} - 4 (- 5) \cdot 2 = 89

x_{1, 2} = \frac{- ( - 7 ) \pm 89}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 89}{2 ( - 5 )}, x_{2} = \frac{- ( - 7 ) - 89}{2 ( - 5 )}

x = \frac{- ( - 7 ) + 89}{2 ( - 5 )} : - \frac{7 + 89}{10}

x = \frac{- ( - 7 ) - 89}{2 ( - 5 )} : \frac{89 - 7}{10}

The solutions to the quadratic equation are:

x = - \frac{7 + 89}{10}, x = \frac{89 - 7}{10}

(2 - 3)^{2}

∣ 3 x + 4 ∣ \geq 2

4 \cdot (x - 10) = - 6 \cdot (2 - x) + 6 x

- 3 x (x - 1) + 8 (x - 3) = 6 x + 7 - 5 x

8 a^{3} + 27

What are the solutions to the equation -5x^2-3x-4x=-2 ?
The solutions to the equation -5x^2-3x-4x=-2 are x=-(7+sqrt(89))/(10),x=(sqrt(89)-7)/(10)
Find the zeros of -5x^2-3x-4x=-2
The zeros of -5x^2-3x-4x=-2 are x=-(7+sqrt(89))/(10),x=(sqrt(89)-7)/(10)