What is factor 2x^2+8x+3x+12 ?

The solution to factor 2x^2+8x+3x+12 is (2x+3)(x+4)

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factor 2x^2+8x+3x+12

factor

2 x^{2} + 8 x + 3 x + 12

(2 x + 3) (x + 4)

Solution steps

2 x^{2} + 8 x + 3 x + 12

Add similar elements:

8 x + 3 x = 11 x

= 2 x^{2} + 11 x + 12

Break the expression into groups

= (2 x^{2} + 3 x) + (8 x + 12)

Factor out

x

from

2 x^{2} + 3 x : x (2 x + 3)

Factor out

4

from

8 x + 12 : 4 (2 x + 3)

= x (2 x + 3) + 4 (2 x + 3)

Factor out common term

2 x + 3

= (2 x + 3) (x + 4)

- 3 \geq 8 (2 + x)

\frac{3 w ^{- 2} x ^{3}}{6 w ^{- 3} x ^{- 2}}

lo g_{7} (14) - lo g_{7} (2)

4 c^{3} + 8 c^{2} - 9 c - 18

1 - 9 a^{2} b^{4}

What is factor 2x^2+8x+3x+12 ?
The solution to factor 2x^2+8x+3x+12 is (2x+3)(x+4)