What are the solutions to the equation x^2-5x=-3x+24 ?

The solutions to the equation x^2-5x=-3x+24 are x=6,x=-4

Find the zeros of x^2-5x=-3x+24

The zeros of x^2-5x=-3x+24 are x=6,x=-4

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x^{2} - 5 x = - 3 x + 24

x = 6, x = - 4

Solution steps

x^{2} - 5 x = - 3 x + 24

Move

24

to the left side

x^{2} - 5 x - 24 = - 3 x

Move

3 x

to the left side

x^{2} - 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 24) = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 1}

x = \frac{- ( - 2 ) + 10}{2 \cdot 1} : 6

x = \frac{- ( - 2 ) - 10}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 6, x = - 4

- 20 x^{2} + 24 x + 32

\frac{3 ^{- 15}}{3 ^{7}} < (3^{- 8}) \cdot (3^{- 9})

- 3 \leq \frac{x - 4}{- 3} < 5

x^{3} + 7 x^{2} - x - 7

What are the solutions to the equation x^2-5x=-3x+24 ?
The solutions to the equation x^2-5x=-3x+24 are x=6,x=-4
Find the zeros of x^2-5x=-3x+24
The zeros of x^2-5x=-3x+24 are x=6,x=-4