What are the solutions to the equation a^2-6a=25 ?

The solutions to the equation a^2-6a=25 are a=3+sqrt(34),a=3-sqrt(34)

Find the zeros of a^2-6a=25

The zeros of a^2-6a=25 are a=3+sqrt(34),a=3-sqrt(34)

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a^{2} - 6 a = 25

a = 3 + 34, a = 3 - 34

Decimal Notation

a = 8.83095 \dots, a = - 2.83095 \dots

Solution steps

a^{2} - 6 a = 25

Move

25

to the left side

a^{2} - 6 a - 25 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 25 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 25) = 234

a_{1, 2} = \frac{- ( - 6 ) \pm 2 34}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 6 ) + 2 34}{2 \cdot 1}, a_{2} = \frac{- ( - 6 ) - 2 34}{2 \cdot 1}

a = \frac{- ( - 6 ) + 2 34}{2 \cdot 1} : 3 + 34

a = \frac{- ( - 6 ) - 2 34}{2 \cdot 1} : 3 - 34

The solutions to the quadratic equation are:

a = 3 + 34, a = 3 - 34

t^{3} - 4 t

49 \cdot 4

- 9 \leq 3 x + 4 \leq \frac{1}{2}

x (2 x + 7) = 245

\frac{25 \cdot 8 \cdot e ^{10}}{24 n ^{2}} \leq 0.0001

What are the solutions to the equation a^2-6a=25 ?
The solutions to the equation a^2-6a=25 are a=3+sqrt(34),a=3-sqrt(34)
Find the zeros of a^2-6a=25
The zeros of a^2-6a=25 are a=3+sqrt(34),a=3-sqrt(34)