What are the solutions to the equation 0=-16x^2+197 ?

The solutions to the equation 0=-16x^2+197 are x=(sqrt(197))/4 ,x=-(sqrt(197))/4

Find the zeros of 0=-16x^2+197

The zeros of 0=-16x^2+197 are x=(sqrt(197))/4 ,x=-(sqrt(197))/4

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0 = - 16 x^{2} + 197

x = \frac{197}{4}, x = - \frac{197}{4}

Decimal Notation

x = 3.50891 \dots, x = - 3.50891 \dots

Solution steps

0 = - 16 x^{2} + 197

Switch sides

- 16 x^{2} + 197 = 0

Move

197

to the right side

- 16 x^{2} = - 197

Divide both sides by

- 16

x^{2} = \frac{197}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{197}{16}, x = - \frac{197}{16}

\frac{197}{16} = \frac{197}{4}

- \frac{197}{16} = - \frac{197}{4}

x = \frac{197}{4}, x = - \frac{197}{4}

x^{2} + 3 x > 40

2 x^{2} - 32 x + 128 = 0

x^{2} + 7 x = 12

- 4 x^{4} + 26 x^{2} - 30

∣ - 2 n ∣ + 10 = - 50

What are the solutions to the equation 0=-16x^2+197 ?
The solutions to the equation 0=-16x^2+197 are x=(sqrt(197))/4 ,x=-(sqrt(197))/4
Find the zeros of 0=-16x^2+197
The zeros of 0=-16x^2+197 are x=(sqrt(197))/4 ,x=-(sqrt(197))/4