What are the solutions to the equation 8p^2-4p=0 ?

The solutions to the equation 8p^2-4p=0 are p= 1/2 ,p=0

Find the zeros of 8p^2-4p=0

The zeros of 8p^2-4p=0 are p= 1/2 ,p=0

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8 p^{2} - 4 p = 0

p = \frac{1}{2}, p = 0

Decimal Notation

p = 0.5, p = 0

Solution steps

8 p^{2} - 4 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 4)^{2} - 4 \cdot 8 \cdot 0 = 4

p_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 8}

Separate the solutions

p_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 8}, p_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 8}

p = \frac{- ( - 4 ) + 4}{2 \cdot 8} : \frac{1}{2}

p = \frac{- ( - 4 ) - 4}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

p = \frac{1}{2}, p = 0

\frac{6 3}{12}

\frac{15 !}{4 ! ( 15 - 4 ) !}

m^{2} + 9 m = 0

m^{3} + 27 n^{3}

- 4 x > - 9 + 8 (- \frac{3}{2} x + 1) - x

What are the solutions to the equation 8p^2-4p=0 ?
The solutions to the equation 8p^2-4p=0 are p= 1/2 ,p=0
Find the zeros of 8p^2-4p=0
The zeros of 8p^2-4p=0 are p= 1/2 ,p=0