What are the solutions to the equation 4m^2-27m-40=0 ?

The solutions to the equation 4m^2-27m-40=0 are m=8,m=-5/4

Find the zeros of 4m^2-27m-40=0

The zeros of 4m^2-27m-40=0 are m=8,m=-5/4

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4 m^{2} - 27 m - 40 = 0

m = 8, m = - \frac{5}{4}

Decimal Notation

m = 8, m = - 1.25

Solution steps

4 m^{2} - 27 m - 40 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 4 ( - 40 )}{2 \cdot 4}

(- 27)^{2} - 4 \cdot 4 (- 40) = 37

m_{1, 2} = \frac{- ( - 27 ) \pm 37}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- ( - 27 ) + 37}{2 \cdot 4}, m_{2} = \frac{- ( - 27 ) - 37}{2 \cdot 4}

m = \frac{- ( - 27 ) + 37}{2 \cdot 4} : 8

m = \frac{- ( - 27 ) - 37}{2 \cdot 4} : - \frac{5}{4}

The solutions to the quadratic equation are:

m = 8, m = - \frac{5}{4}

1 + \frac{3 x}{8} - \frac{1}{3} (x + 8) \geq x

\frac{16 - c ^{2}}{c ^{2} + c - 20}

x^{3} - 5 > 0

2 ∣ 3 - x ∣ - 10 \geq 0

- \frac{3 π}{4} + 2 π

What are the solutions to the equation 4m^2-27m-40=0 ?
The solutions to the equation 4m^2-27m-40=0 are m=8,m=-5/4
Find the zeros of 4m^2-27m-40=0
The zeros of 4m^2-27m-40=0 are m=8,m=-5/4