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Popular >

8+|1-x/2 |>= 10

Solution

8 + 1 - \frac{x}{2} \geq 10

Solution

x \leq - 2 or x \geq 6

+1

Interval Notation

(- \infty, - 2] \cup [6, \infty)

Solution steps

8 + 1 - \frac{x}{2} \geq 10

Move

8

to the right side

1 - \frac{x}{2} \geq 2

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

1 - \frac{x}{2} \leq - 2 or 1 - \frac{x}{2} \geq 2

1 - \frac{x}{2} \leq - 2 or 1 - \frac{x}{2} \geq 2

x \leq - 2 or x \geq 6

Popular Examples

factor 27y^2-12x^2 factor

27 y^{2} - 12 x^{2}

(x-5)(x+1)(3-x)>= 0

(x - 5) (x + 1) (3 - x) \geq 0

factor n^2+7n+6 factor

n^{2} + 7 n + 6

factor x^2y^2-16 factor

x^{2} y^{2} - 16

6 - 3 + 4 x + 1 = 4 x + 5

Frequently Asked Questions (FAQ)

What is 8+|1-x/2 |>= 10 ?
The solution to 8+|1-x/2 |>= 10 is x<=-2\lor x>= 6