What are the solutions to the equation x^2+912x=3 ?

The solutions to the equation x^2+912x=3 are x=-456+sqrt(207939),x=-456-sqrt(207939)

Find the zeros of x^2+912x=3

The zeros of x^2+912x=3 are x=-456+sqrt(207939),x=-456-sqrt(207939)

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x^{2} + 912 x = 3

x = - 456 + 207939, x = - 456 - 207939

Decimal Notation

x = 0.00328 \dots, x = - 912.00328 \dots

Solution steps

x^{2} + 912 x = 3

Move

3

to the left side

x^{2} + 912 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 912 \pm 91 2 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

91 2^{2} - 4 \cdot 1 \cdot (- 3) = 2207939

x_{1, 2} = \frac{- 912 \pm 2 207939}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 912 + 2 207939}{2 \cdot 1}, x_{2} = \frac{- 912 - 2 207939}{2 \cdot 1}

x = \frac{- 912 + 2 207939}{2 \cdot 1} : - 456 + 207939

x = \frac{- 912 - 2 207939}{2 \cdot 1} : - 456 - 207939

The solutions to the quadratic equation are:

x = - 456 + 207939, x = - 456 - 207939

(3 x)^{- 2}

12 x^{2} - 36 x y + 27 y^{2}

22 = - 11 k

8 x^{2} - 30 x + 25

9 - w^{2} - (3 - w)^{2}

What are the solutions to the equation x^2+912x=3 ?
The solutions to the equation x^2+912x=3 are x=-456+sqrt(207939),x=-456-sqrt(207939)
Find the zeros of x^2+912x=3
The zeros of x^2+912x=3 are x=-456+sqrt(207939),x=-456-sqrt(207939)