What are the solutions to the equation x^2-16x-17=0 ?

The solutions to the equation x^2-16x-17=0 are x=17,x=-1

Find the zeros of x^2-16x-17=0

The zeros of x^2-16x-17=0 are x=17,x=-1

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x^{2} - 16 x - 17 = 0

x = 17, x = - 1

Solution steps

x^{2} - 16 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 17) = 18

x_{1, 2} = \frac{- ( - 16 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 18}{2 \cdot 1}

x = \frac{- ( - 16 ) + 18}{2 \cdot 1} : 17

x = \frac{- ( - 16 ) - 18}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 17, x = - 1

7 (\frac{2}{3})

- 3 11 r + 3 \geq - 15

\frac{7}{3} (\frac{1}{2} v - \frac{10}{3}) = - \frac{35}{3} - \frac{1}{2} v

5 (x - 2)^{2} + 6 = 86

6 a^{2} - 11 a + 4

What are the solutions to the equation x^2-16x-17=0 ?
The solutions to the equation x^2-16x-17=0 are x=17,x=-1
Find the zeros of x^2-16x-17=0
The zeros of x^2-16x-17=0 are x=17,x=-1