What are the solutions to the equation 4x^2-3x=1 ?

The solutions to the equation 4x^2-3x=1 are x=1,x=-1/4

Find the zeros of 4x^2-3x=1

The zeros of 4x^2-3x=1 are x=1,x=-1/4

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4 x^{2} - 3 x = 1

x = 1, x = - \frac{1}{4}

Decimal Notation

x = 1, x = - 0.25

Solution steps

4 x^{2} - 3 x = 1

Move

1

to the left side

4 x^{2} - 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 (- 1) = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 4}, x_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 4}

x = \frac{- ( - 3 ) + 5}{2 \cdot 4} : 1

x = \frac{- ( - 3 ) - 5}{2 \cdot 4} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{4}

lo g_{9} (x + 2) > lo g_{9} (6 - 3 x)

2 - 2 i

\frac{x}{2} - 8 > 18

1 - \frac{16}{9}

18 x^{4} - 12 x^{2}

What are the solutions to the equation 4x^2-3x=1 ?
The solutions to the equation 4x^2-3x=1 are x=1,x=-1/4
Find the zeros of 4x^2-3x=1
The zeros of 4x^2-3x=1 are x=1,x=-1/4