What are the solutions to the equation x^2-2+x^2+5x-9+(-8x-42)+x=360 ?

The solutions to the equation x^2-2+x^2+5x-9+(-8x-42)+x=360 are x=(1+sqrt(827))/2 ,x=(1-sqrt(827))/2

Find the zeros of x^2-2+x^2+5x-9+(-8x-42)+x=360

The zeros of x^2-2+x^2+5x-9+(-8x-42)+x=360 are x=(1+sqrt(827))/2 ,x=(1-sqrt(827))/2

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x^{2} - 2 + x^{2} + 5 x - 9 + (- 8 x - 42) + x = 360

x = \frac{1 + 827}{2}, x = \frac{1 - 827}{2}

Decimal Notation

x = 14.87880 \dots, x = - 13.87880 \dots

Solution steps

x^{2} - 2 + x^{2} + 5 x - 9 + (- 8 x - 42) + x = 360

Refine

2 x^{2} - 2 x - 53 = 360

Move

360

to the left side

2 x^{2} - 2 x - 413 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 413 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 413) = 2827

x_{1, 2} = \frac{- ( - 2 ) \pm 2 827}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 827}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 2 827}{2 \cdot 2}

x = \frac{- ( - 2 ) + 2 827}{2 \cdot 2} : \frac{1 + 827}{2}

x = \frac{- ( - 2 ) - 2 827}{2 \cdot 2} : \frac{1 - 827}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 827}{2}, x = \frac{1 - 827}{2}

\frac{2}{5} + \frac{3}{4} \cdot \frac{1}{5} + 3 - \frac{7}{4}

22 = 1.5 + \frac{1 1 ^{2} + y ^{2}}{- 19.6}

x^{2} + 9 x - 70 = 0

\frac{x + 5}{16} = 1

3 v^{2} + 16 v + 5

What are the solutions to the equation x^2-2+x^2+5x-9+(-8x-42)+x=360 ?
The solutions to the equation x^2-2+x^2+5x-9+(-8x-42)+x=360 are x=(1+sqrt(827))/2 ,x=(1-sqrt(827))/2
Find the zeros of x^2-2+x^2+5x-9+(-8x-42)+x=360
The zeros of x^2-2+x^2+5x-9+(-8x-42)+x=360 are x=(1+sqrt(827))/2 ,x=(1-sqrt(827))/2