What are the solutions to the equation -16x^2+176x=0 ?

The solutions to the equation -16x^2+176x=0 are x=0,x=11

Find the zeros of -16x^2+176x=0

The zeros of -16x^2+176x=0 are x=0,x=11

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- 16 x^{2} + 176 x = 0

x = 0, x = 11

Solution steps

- 16 x^{2} + 176 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 176 \pm 17 6 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

17 6^{2} - 4 (- 16) \cdot 0 = 176

x_{1, 2} = \frac{- 176 \pm 176}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 176 + 176}{2 ( - 16 )}, x_{2} = \frac{- 176 - 176}{2 ( - 16 )}

x = \frac{- 176 + 176}{2 ( - 16 )} : 0

x = \frac{- 176 - 176}{2 ( - 16 )} : 11

The solutions to the quadratic equation are:

x = 0, x = 11

12 (x - 4) = - 108

- 8 \cdot 2

10 n < - 60

a^{10} - 49 b^{12}

What are the solutions to the equation -16x^2+176x=0 ?
The solutions to the equation -16x^2+176x=0 are x=0,x=11
Find the zeros of -16x^2+176x=0
The zeros of -16x^2+176x=0 are x=0,x=11