What is factor 121n^2-66n+9 ?

The solution to factor 121n^2-66n+9 is (11n-3)^2

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factor 121n^2-66n+9

factor

121 n^{2} - 66 n + 9

(11 n - 3)^{2}

Solution steps

121 n^{2} - 66 n + 9

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

121 n^{2} = (11 n)^{2}

9 = 3^{2}

- 66 n = - 2 \cdot 11 n \cdot 3

= (11 n)^{2} - 2 \cdot 11 n \cdot 3 + 3^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(11 n)^{2} - 2 \cdot 11 n \cdot 3 + 3^{2} = (11 n - 3)^{2}

= (11 n - 3)^{2}

(\frac{a ^{2}}{b})^{5} (\frac{a ^{3} b ^{2}}{c ^{3}})^{3}

(4 - 7 i)^{2}

5 x - 5 = x + 11

x^{2} + 14 x - 15 = 0