What are the solutions to the equation x(x-2)=15 ?

The solutions to the equation x(x-2)=15 are x=5,x=-3

Find the zeros of x(x-2)=15

The zeros of x(x-2)=15 are x=5,x=-3

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x (x - 2) = 15

x = 5, x = - 3

Solution steps

x (x - 2) = 15

Expand

x (x - 2) : x^{2} - 2 x

x^{2} - 2 x = 15

Move

15

to the left side

x^{2} - 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

x_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

x = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

x = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 5, x = - 3

(x - 5) (x - 2) (x + 7) > 0

\frac{1}{3} x^{2} - \frac{1}{9} x + \frac{10}{9} = 0

0.64 7^{2} - 0.179 \cdot 0.647 - 0.368 \cdot 0.647

36 x^{2} y^{6} - 16

(x + 3)^{2}

What are the solutions to the equation x(x-2)=15 ?
The solutions to the equation x(x-2)=15 are x=5,x=-3
Find the zeros of x(x-2)=15
The zeros of x(x-2)=15 are x=5,x=-3