What are the solutions to the equation 5yy-6y+1=0 ?

The solutions to the equation 5yy-6y+1=0 are y=1,y= 1/5

Find the zeros of 5yy-6y+1=0

The zeros of 5yy-6y+1=0 are y=1,y= 1/5

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5 yy - 6 y + 1 = 0

y = 1, y = \frac{1}{5}

Decimal Notation

y = 1, y = 0.2

Solution steps

5 yy - 6 y + 1 = 0

Expand

5 yy - 6 y + 1 : 5 y^{2} - 6 y + 1

5 y^{2} - 6 y + 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

(- 6)^{2} - 4 \cdot 5 \cdot 1 = 4

y_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 5}, y_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 5}

y = \frac{- ( - 6 ) + 4}{2 \cdot 5} : 1

y = \frac{- ( - 6 ) - 4}{2 \cdot 5} : \frac{1}{5}

The solutions to the quadratic equation are:

y = 1, y = \frac{1}{5}

2 (- \frac{2}{3})^{2} + 5 (- \frac{2}{3}) + 6

\frac{9 ^{2}}{9 ^{2} - 4} - \frac{1}{9 - 2}

(100 - 21) (100 + 21)

3 x^{4} + 6 x^{3} + 6 x^{2} + 6 x + 3

\frac{7}{8} x \geq 8

What are the solutions to the equation 5yy-6y+1=0 ?
The solutions to the equation 5yy-6y+1=0 are y=1,y= 1/5
Find the zeros of 5yy-6y+1=0
The zeros of 5yy-6y+1=0 are y=1,y= 1/5