What is factor 9n^2+4a^2-12an ?

The solution to factor 9n^2+4a^2-12an is (2a-3n)^2

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factor 9n^2+4a^2-12an

factor

9 n^{2} + 4 a^{2} - 12 an

(2 a - 3 n)^{2}

Solution steps

9 n^{2} + 4 a^{2} - 12 an

Group by common factors

= 4 a^{2} - 12 an + 9 n^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 a^{2} = (2 a)^{2}

9 n^{2} = (3 n)^{2}

- 12 an = - 2 \cdot 2 a \cdot 3 n

= (2 a)^{2} - 2 \cdot 2 a \cdot 3 n + (3 n)^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(2 a)^{2} - 2 \cdot 2 a \cdot 3 n + (3 n)^{2} = (2 a - 3 n)^{2}

= (2 a - 3 n)^{2}

x^{3} + 343

x + 9 \leq 8

\frac{5}{7}

2.5 (4 x + 4.5) + 2 x + 4.5 = 4.5 x

\frac{x}{3} - 2 = \frac{5}{3} x + 7

What is factor 9n^2+4a^2-12an ?
The solution to factor 9n^2+4a^2-12an is (2a-3n)^2