What are the solutions to the equation x^2-8x-64=0 ?

The solutions to the equation x^2-8x-64=0 are x=4(1+sqrt(5)),x=4(1-sqrt(5))

Find the zeros of x^2-8x-64=0

The zeros of x^2-8x-64=0 are x=4(1+sqrt(5)),x=4(1-sqrt(5))

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x^{2} - 8 x - 64 = 0

x = 4 (1 + 5), x = 4 (1 - 5)

Decimal Notation

x = 12.94427 \dots, x = - 4.94427 \dots

Solution steps

x^{2} - 8 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 64 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 64) = 85

x_{1, 2} = \frac{- ( - 8 ) \pm 8 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 5}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8 5}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8 5}{2 \cdot 1} : 4 (1 + 5)

x = \frac{- ( - 8 ) - 8 5}{2 \cdot 1} : 4 (1 - 5)

The solutions to the quadratic equation are:

x = 4 (1 + 5), x = 4 (1 - 5)

\frac{π}{3} + \frac{π}{10}

x + (- 3) < - 9

3 x - 2 \leq 10 or 4 x + 3 \geq - 21

x^{2} \cdot x^{- \frac{1}{2}}

- 12 < 2 z + 2 < - 2

What are the solutions to the equation x^2-8x-64=0 ?
The solutions to the equation x^2-8x-64=0 are x=4(1+sqrt(5)),x=4(1-sqrt(5))
Find the zeros of x^2-8x-64=0
The zeros of x^2-8x-64=0 are x=4(1+sqrt(5)),x=4(1-sqrt(5))