What are the solutions to the equation 21^2+x^2=51^2 ?

The solutions to the equation 21^2+x^2=51^2 are x=12sqrt(15),x=-12sqrt(15)

Find the zeros of 21^2+x^2=51^2

The zeros of 21^2+x^2=51^2 are x=12sqrt(15),x=-12sqrt(15)

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2 1^{2} + x^{2} = 5 1^{2}

x = 1215, x = - 1215

Decimal Notation

x = 46.47580 \dots, x = - 46.47580 \dots

Solution steps

2 1^{2} + x^{2} = 5 1^{2}

Move

2 1^{2}

to the right side

x^{2} = 2160

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2160, x = - 2160

2160 = 1215

- 2160 = - 1215

x = 1215, x = - 1215

x^{2} + 17 x + 60

27 w^{5} - 75 w

49 - 4 y^{2}

\frac{v}{20} + 7 < 8

x^{2} y^{2} - a^{2} y^{2} - b^{2} x^{2} + a^{2} b^{2}

What are the solutions to the equation 21^2+x^2=51^2 ?
The solutions to the equation 21^2+x^2=51^2 are x=12sqrt(15),x=-12sqrt(15)
Find the zeros of 21^2+x^2=51^2
The zeros of 21^2+x^2=51^2 are x=12sqrt(15),x=-12sqrt(15)