What are the solutions to the equation 63=2w^2+5w ?

The solutions to the equation 63=2w^2+5w are w= 9/2 ,w=-7

Find the zeros of 63=2w^2+5w

The zeros of 63=2w^2+5w are w= 9/2 ,w=-7

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63 = 2 w^{2} + 5 w

w = \frac{9}{2}, w = - 7

Decimal Notation

w = 4.5, w = - 7

Solution steps

63 = 2 w^{2} + 5 w

Switch sides

2 w^{2} + 5 w = 63

Move

63

to the left side

2 w^{2} + 5 w - 63 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 63 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 63) = 23

w_{1, 2} = \frac{- 5 \pm 23}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- 5 + 23}{2 \cdot 2}, w_{2} = \frac{- 5 - 23}{2 \cdot 2}

w = \frac{- 5 + 23}{2 \cdot 2} : \frac{9}{2}

w = \frac{- 5 - 23}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

w = \frac{9}{2}, w = - 7

3 x^{2} + 5 x - 28

\frac{x}{4} + 1 > 10

y^{2} - 5 y + 6

\frac{25}{4} + 2

2 x (x - 1) = 3

What are the solutions to the equation 63=2w^2+5w ?
The solutions to the equation 63=2w^2+5w are w= 9/2 ,w=-7
Find the zeros of 63=2w^2+5w
The zeros of 63=2w^2+5w are w= 9/2 ,w=-7