What is 12x-39<= 9\land-4x+3<-6 ?

The solution to 12x-39<= 9\land-4x+3<-6 is 9/4 <x<= 4

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12x-39<= 9\land-4x+3<-6

12 x - 39 \leq 9 and - 4 x + 3 < - 6

\frac{9}{4} < x \leq 4

Interval Notation

(\frac{9}{4}, 4]

Decimal Notation

2.25 < x \leq 4

Solution steps

12 x - 39 \leq 9 and - 4 x + 3 < - 6

12 x - 39 \leq 9 : x \leq 4

- 4 x + 3 < - 6 : x > \frac{9}{4}

Combine the intervals

x \leq 4 and x > \frac{9}{4}

Merge Overlapping Intervals

\frac{9}{4} < x \leq 4

5 x - 13 = 8 - 2 x

5 y + 3 + 2 y = 24

x - 5 = 7

∣ x + 2 ∣ < 1

\frac{x + 2}{2 x - 3} < 4

What is 12x-39<= 9\land-4x+3<-6 ?
The solution to 12x-39<= 9\land-4x+3<-6 is 9/4 <x<= 4