What are the solutions to the equation p^2+14p-38=0 ?

The solutions to the equation p^2+14p-38=0 are p=-7+sqrt(87),p=-7-sqrt(87)

Find the zeros of p^2+14p-38=0

The zeros of p^2+14p-38=0 are p=-7+sqrt(87),p=-7-sqrt(87)

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p^{2} + 14 p - 38 = 0

p = - 7 + 87, p = - 7 - 87

Decimal Notation

p = 2.32737 \dots, p = - 16.32737 \dots

Solution steps

p^{2} + 14 p - 38 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 38 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 38) = 287

p_{1, 2} = \frac{- 14 \pm 2 87}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 14 + 2 87}{2 \cdot 1}, p_{2} = \frac{- 14 - 2 87}{2 \cdot 1}

p = \frac{- 14 + 2 87}{2 \cdot 1} : - 7 + 87

p = \frac{- 14 - 2 87}{2 \cdot 1} : - 7 - 87

The solutions to the quadratic equation are:

p = - 7 + 87, p = - 7 - 87

(\frac{( 17.48 - x \cdot 20.56 )}{23.44}) \cdot 862 + x \cdot 825 = 698

(\frac{1}{4} x^{3}) (8 x^{4})

p + 12 = 30

(3 x^{5})^{3}

4 w^{2} + 12 w + 9 = 25

What are the solutions to the equation p^2+14p-38=0 ?
The solutions to the equation p^2+14p-38=0 are p=-7+sqrt(87),p=-7-sqrt(87)
Find the zeros of p^2+14p-38=0
The zeros of p^2+14p-38=0 are p=-7+sqrt(87),p=-7-sqrt(87)