What are the solutions to the equation 3z^2+8z+5=0 ?

The solutions to the equation 3z^2+8z+5=0 are z=-1,z=-5/3

Find the zeros of 3z^2+8z+5=0

The zeros of 3z^2+8z+5=0 are z=-1,z=-5/3

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3 z^{2} + 8 z + 5 = 0

z = - 1, z = - \frac{5}{3}

Decimal Notation

z = - 1, z = - 1.66666 \dots

Solution steps

3 z^{2} + 8 z + 5 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

8^{2} - 4 \cdot 3 \cdot 5 = 2

z_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- 8 + 2}{2 \cdot 3}, z_{2} = \frac{- 8 - 2}{2 \cdot 3}

z = \frac{- 8 + 2}{2 \cdot 3} : - 1

z = \frac{- 8 - 2}{2 \cdot 3} : - \frac{5}{3}

The solutions to the quadratic equation are:

z = - 1, z = - \frac{5}{3}

∣ x + 4 ∣ = ∣ 4 - x ∣

- 11 b + 90 = - 2 b

\frac{18 x ^{5} y ^{2}}{24 x ^{7} y ^{2}}

\frac{( x - 1 ) ^{3} ( x + 2 ) ^{2}}{( x + 4 ) ^{2}} > 0

x + 12 \leq 4

What are the solutions to the equation 3z^2+8z+5=0 ?
The solutions to the equation 3z^2+8z+5=0 are z=-1,z=-5/3
Find the zeros of 3z^2+8z+5=0
The zeros of 3z^2+8z+5=0 are z=-1,z=-5/3