What are the solutions to the equation x^2+(x+7)^2=(x+9)^2 ?

The solutions to the equation x^2+(x+7)^2=(x+9)^2 are x=8,x=-4

Find the zeros of x^2+(x+7)^2=(x+9)^2

The zeros of x^2+(x+7)^2=(x+9)^2 are x=8,x=-4

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x^{2} + (x + 7)^{2} = (x + 9)^{2}

x = 8, x = - 4

Solution steps

x^{2} + (x + 7)^{2} = (x + 9)^{2}

Expand

x^{2} + (x + 7)^{2} : 2 x^{2} + 14 x + 49

Expand

(x + 9)^{2} : x^{2} + 18 x + 81

2 x^{2} + 14 x + 49 = x^{2} + 18 x + 81

Move

81

to the left side

2 x^{2} + 14 x - 32 = x^{2} + 18 x

Move

18 x

to the left side

2 x^{2} - 4 x - 32 = x^{2}

Move

x^{2}

to the left side

x^{2} - 4 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 32) = 12

x_{1, 2} = \frac{- ( - 4 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 12}{2 \cdot 1}

x = \frac{- ( - 4 ) + 12}{2 \cdot 1} : 8

x = \frac{- ( - 4 ) - 12}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 8, x = - 4

2 w^{2} + 9 w + 10

9150 - 24

55 c + 13 \leq 75 c + 3955 c + 13 \leq 75 c + 39

- 175 - 47

(5 x)^{0}

What are the solutions to the equation x^2+(x+7)^2=(x+9)^2 ?
The solutions to the equation x^2+(x+7)^2=(x+9)^2 are x=8,x=-4
Find the zeros of x^2+(x+7)^2=(x+9)^2
The zeros of x^2+(x+7)^2=(x+9)^2 are x=8,x=-4