What are the solutions to the equation r^2+r-1=0 ?

The solutions to the equation r^2+r-1=0 are r=(-1+sqrt(5))/2 ,r=(-1-sqrt(5))/2

Find the zeros of r^2+r-1=0

The zeros of r^2+r-1=0 are r=(-1+sqrt(5))/2 ,r=(-1-sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} + r - 1 = 0

r = \frac{- 1 + 5}{2}, r = \frac{- 1 - 5}{2}

Decimal Notation

r = 0.61803 \dots, r = - 1.61803 \dots

Solution steps

r^{2} + r - 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 1) = 5

r_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 1 + 5}{2 \cdot 1}, r_{2} = \frac{- 1 - 5}{2 \cdot 1}

r = \frac{- 1 + 5}{2 \cdot 1} : \frac{- 1 + 5}{2}

r = \frac{- 1 - 5}{2 \cdot 1} : \frac{- 1 - 5}{2}

The solutions to the quadratic equation are:

r = \frac{- 1 + 5}{2}, r = \frac{- 1 - 5}{2}

2 (9)^{\frac{1}{2}}

r^{2} + 200 r + 10 = 0

(a - b) \cdot z + 3 \cdot (b - a)

4 h^{2} + 4 h - 3

9 - ∣ 3 x + 9 ∣ = 6

What are the solutions to the equation r^2+r-1=0 ?
The solutions to the equation r^2+r-1=0 are r=(-1+sqrt(5))/2 ,r=(-1-sqrt(5))/2
Find the zeros of r^2+r-1=0
The zeros of r^2+r-1=0 are r=(-1+sqrt(5))/2 ,r=(-1-sqrt(5))/2