What are the solutions to the equation (x+6)(x-2)=20 ?

The solutions to the equation (x+6)(x-2)=20 are x=4,x=-8

Find the zeros of (x+6)(x-2)=20

The zeros of (x+6)(x-2)=20 are x=4,x=-8

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(x + 6) (x - 2) = 20

x = 4, x = - 8

Solution steps

(x + 6) (x - 2) = 20

Expand

(x + 6) (x - 2) : x^{2} + 4 x - 12

x^{2} + 4 x - 12 = 20

Move

20

to the left side

x^{2} + 4 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 32) = 12

x_{1, 2} = \frac{- 4 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 12}{2 \cdot 1}, x_{2} = \frac{- 4 - 12}{2 \cdot 1}

x = \frac{- 4 + 12}{2 \cdot 1} : 4

x = \frac{- 4 - 12}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 4, x = - 8

\frac{- 7}{8} \leq m \frac{- 13}{8}

lo g_{6} (3) + lo g_{6} (2)

5^{\frac{2}{5}}

10 (x - 1) - 7 x = x

- 2.2 t + 3.5 = - 5.1 t + 6.4

What are the solutions to the equation (x+6)(x-2)=20 ?
The solutions to the equation (x+6)(x-2)=20 are x=4,x=-8
Find the zeros of (x+6)(x-2)=20
The zeros of (x+6)(x-2)=20 are x=4,x=-8