What are the solutions to the equation 1/3 x^2-5x+28=0 ?

The solutions to the equation 1/3 x^2-5x+28=0 are x= 15/2+i(sqrt(111))/2 ,x= 15/2-i(sqrt(111))/2

Find the zeros of 1/3 x^2-5x+28=0

The zeros of 1/3 x^2-5x+28=0 are x= 15/2+i(sqrt(111))/2 ,x= 15/2-i(sqrt(111))/2

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\frac{1}{3} x^{2} - 5 x + 28 = 0

x = \frac{15}{2} + i \frac{111}{2}, x = \frac{15}{2} - i \frac{111}{2}

Solution steps

\frac{1}{3} x^{2} - 5 x + 28 = 0

Multiply both sides by

3

x^{2} - 15 x + 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 84}{2 \cdot 1}

Simplify

(- 15)^{2} - 4 \cdot 1 \cdot 84 : 111 i

x_{1, 2} = \frac{- ( - 15 ) \pm 111 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 111 i}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 111 i}{2 \cdot 1}

x = \frac{- ( - 15 ) + 111 i}{2 \cdot 1} : \frac{15}{2} + i \frac{111}{2}

x = \frac{- ( - 15 ) - 111 i}{2 \cdot 1} : \frac{15}{2} - i \frac{111}{2}

The solutions to the quadratic equation are:

x = \frac{15}{2} + i \frac{111}{2}, x = \frac{15}{2} - i \frac{111}{2}

7 (x - 2) = 7 x + 14

(- 2 \frac{2}{3})^{2}

6 \cdot \frac{1}{5}

81 - 24 x^{3}

0 = - 5 t^{2}

What are the solutions to the equation 1/3 x^2-5x+28=0 ?
The solutions to the equation 1/3 x^2-5x+28=0 are x= 15/2+i(sqrt(111))/2 ,x= 15/2-i(sqrt(111))/2
Find the zeros of 1/3 x^2-5x+28=0
The zeros of 1/3 x^2-5x+28=0 are x= 15/2+i(sqrt(111))/2 ,x= 15/2-i(sqrt(111))/2