What are the solutions to the equation 14x^2+14x=3 ?

The solutions to the equation 14x^2+14x=3 are x=(-7+sqrt(91))/(14),x=-(7+sqrt(91))/(14)

Find the zeros of 14x^2+14x=3

The zeros of 14x^2+14x=3 are x=(-7+sqrt(91))/(14),x=-(7+sqrt(91))/(14)

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14 x^{2} + 14 x = 3

x = \frac{- 7 + 91}{14}, x = - \frac{7 + 91}{14}

Decimal Notation

x = 0.18138 \dots, x = - 1.18138 \dots

Solution steps

14 x^{2} + 14 x = 3

Move

3

to the left side

14 x^{2} + 14 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 14 ( - 3 )}{2 \cdot 14}

1 4^{2} - 4 \cdot 14 (- 3) = 291

x_{1, 2} = \frac{- 14 \pm 2 91}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- 14 + 2 91}{2 \cdot 14}, x_{2} = \frac{- 14 - 2 91}{2 \cdot 14}

x = \frac{- 14 + 2 91}{2 \cdot 14} : \frac{- 7 + 91}{14}

x = \frac{- 14 - 2 91}{2 \cdot 14} : - \frac{7 + 91}{14}

The solutions to the quadratic equation are:

x = \frac{- 7 + 91}{14}, x = - \frac{7 + 91}{14}

\frac{4}{5} - \frac{2}{7}

m^{2} + 2 mn - 24 n^{2}

- \frac{1}{- 2}

p - 18 = 563

\frac{10 !}{4 !}

What are the solutions to the equation 14x^2+14x=3 ?
The solutions to the equation 14x^2+14x=3 are x=(-7+sqrt(91))/(14),x=-(7+sqrt(91))/(14)
Find the zeros of 14x^2+14x=3
The zeros of 14x^2+14x=3 are x=(-7+sqrt(91))/(14),x=-(7+sqrt(91))/(14)