What is (1-i)(-sqrt(2)+i) ?

The solution to (1-i)(-sqrt(2)+i) is (-sqrt(2)+1)+(1+sqrt(2))i

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simplify (1-i)(-sqrt(2)+i)

simplify

(1 - i) (- 2 + i)

(- 2 + 1) + (1 + 2) i

Solution steps

(1 - i) (- 2 + i)

Apply complex arithmetic rule:

(a + bi) (c + d i) = (a c - b d) + (a d + b c) i

= (1 \cdot (- 2) - (- 1) \cdot 1) + (1 \cdot 1 - 1 \cdot (- 2)) i

Simplify

(1 \cdot (- 2) - (- 1) \cdot 1) + (1 \cdot 1 - 1 \cdot (- 2)) i : (- 2 + 1) + (1 + 2) i

= (- 2 + 1) + (1 + 2) i

- 14.5 = 0.5 x - 14.5

42 + y = 86

- 9 + 3 - 16

(\frac{a ^{4} b ^{3}}{2 a ^{3} b ^{4} \cdot 2 a ^{2} b ^{4}})^{3}

- 6 n = - 8

What is (1-i)(-sqrt(2)+i) ?
The solution to (1-i)(-sqrt(2)+i) is (-sqrt(2)+1)+(1+sqrt(2))i