What are the solutions to the equation 4x^2=10+3x ?

The solutions to the equation 4x^2=10+3x are x=2,x=-5/4

Find the zeros of 4x^2=10+3x

The zeros of 4x^2=10+3x are x=2,x=-5/4

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4 x^{2} = 10 + 3 x

x = 2, x = - \frac{5}{4}

Solution steps

4 x^{2} = 10 + 3 x

Move

3 x

to the left side

4 x^{2} - 3 x = 10

Move

10

to the left side

4 x^{2} - 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 ( - 10 )}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 (- 10) = 13

x_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 13}{2 \cdot 4}, x_{2} = \frac{- ( - 3 ) - 13}{2 \cdot 4}

x = \frac{- ( - 3 ) + 13}{2 \cdot 4} : 2

x = \frac{- ( - 3 ) - 13}{2 \cdot 4} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = 2, x = - \frac{5}{4}

\frac{1}{2 k} + \frac{4}{k} - \frac{k}{k + 2}

3 x + 21

9 x^{2} + 12 x = 4

15 x^{2} + x - 6

x^{2} - 9 = 0

What are the solutions to the equation 4x^2=10+3x ?
The solutions to the equation 4x^2=10+3x are x=2,x=-5/4
Find the zeros of 4x^2=10+3x
The zeros of 4x^2=10+3x are x=2,x=-5/4