What are the solutions to the equation 26x^2-27x+1=0 ?

The solutions to the equation 26x^2-27x+1=0 are x=1,x= 1/26

Find the zeros of 26x^2-27x+1=0

The zeros of 26x^2-27x+1=0 are x=1,x= 1/26

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26 x^{2} - 27 x + 1 = 0

x = 1, x = \frac{1}{26}

Decimal Notation

x = 1, x = 0.03846 \dots

Solution steps

26 x^{2} - 27 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 26 \cdot 1}{2 \cdot 26}

(- 27)^{2} - 4 \cdot 26 \cdot 1 = 25

x_{1, 2} = \frac{- ( - 27 ) \pm 25}{2 \cdot 26}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 25}{2 \cdot 26}, x_{2} = \frac{- ( - 27 ) - 25}{2 \cdot 26}

x = \frac{- ( - 27 ) + 25}{2 \cdot 26} : 1

x = \frac{- ( - 27 ) - 25}{2 \cdot 26} : \frac{1}{26}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{26}

8 (w + 2) = 40

(3 x^{- 2} y) (6 x y^{- 3})

2 x^{2} + 3 x - 2 < 1

\frac{3}{5} - \frac{3}{10}

(8^{\frac{2}{3}})^{4}

What are the solutions to the equation 26x^2-27x+1=0 ?
The solutions to the equation 26x^2-27x+1=0 are x=1,x= 1/26
Find the zeros of 26x^2-27x+1=0
The zeros of 26x^2-27x+1=0 are x=1,x= 1/26