What are the solutions to the equation -x^2-x+6=0 ?

The solutions to the equation -x^2-x+6=0 are x=-3,x=2

Find the zeros of -x^2-x+6=0

The zeros of -x^2-x+6=0 are x=-3,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} - x + 6 = 0

x = - 3, x = 2

Solution steps

- x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 6 = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 5}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 5}{2 ( - 1 )} : - 3

x = \frac{- ( - 1 ) - 5}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 3, x = 2

- 2 c^{2} - 68 c - 186

2 x + 16 = 3 x - 4 (x + 2)

x^{5} + y^{5}

x^{\frac{1}{2}} (x)

\frac{3 x}{4} - \frac{1}{2} = \frac{x - 2}{6}

What are the solutions to the equation -x^2-x+6=0 ?
The solutions to the equation -x^2-x+6=0 are x=-3,x=2
Find the zeros of -x^2-x+6=0
The zeros of -x^2-x+6=0 are x=-3,x=2