What is factor (8x^2+2x)+(4x+1) ?

The solution to factor (8x^2+2x)+(4x+1) is (4x+1)(2x+1)

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factor (8x^2+2x)+(4x+1)

factor

(8 x^{2} + 2 x) + (4 x + 1)

(4 x + 1) (2 x + 1)

Solution steps

(8 x^{2} + 2 x) + (4 x + 1)

Factor

8 x^{2} + 2 x : 2 x (4 x + 1)

= 2 x (4 x + 1) + (4 x + 1)

Factor out common term

(4 x + 1) : (4 x + 1) (2 x + 1)

= (4 x + 1) (2 x + 1)

2 a (x + y) + b (x + y)

x^{2} - 2 x < 0

6 (x + 1) - 9 = 4 (x - 1) + 2 x

\frac{3 x}{4} = 18

lo g_{4} (32) - lo g_{4} (2)

What is factor (8x^2+2x)+(4x+1) ?
The solution to factor (8x^2+2x)+(4x+1) is (4x+1)(2x+1)