What are the solutions to the equation w^2-40=3w ?

The solutions to the equation w^2-40=3w are w=8,w=-5

Find the zeros of w^2-40=3w

The zeros of w^2-40=3w are w=8,w=-5

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w^{2} - 40 = 3 w

w = 8, w = - 5

Solution steps

w^{2} - 40 = 3 w

Move

3 w

to the left side

w^{2} - 40 - 3 w = 0

Write in the standard form

a x^{2} + b x + c = 0

w^{2} - 3 w - 40 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 40) = 13

w_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 3 ) + 13}{2 \cdot 1}, w_{2} = \frac{- ( - 3 ) - 13}{2 \cdot 1}

w = \frac{- ( - 3 ) + 13}{2 \cdot 1} : 8

w = \frac{- ( - 3 ) - 13}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

w = 8, w = - 5

\frac{x}{4} + 1 = \frac{x}{2}

1 - (2 y - 3)^{2}

12 ab - 8 a

(x - 3)^{2} (x + 3)^{2}

3 x^{2} - 12 x + 11 = x

What are the solutions to the equation w^2-40=3w ?
The solutions to the equation w^2-40=3w are w=8,w=-5
Find the zeros of w^2-40=3w
The zeros of w^2-40=3w are w=8,w=-5