What are the solutions to the equation r^2+4r=0 ?

The solutions to the equation r^2+4r=0 are r=0,r=-4

Find the zeros of r^2+4r=0

The zeros of r^2+4r=0 are r=0,r=-4

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r^{2} + 4 r = 0

r = 0, r = - 4

Solution steps

r^{2} + 4 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

r_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 4 + 4}{2 \cdot 1}, r_{2} = \frac{- 4 - 4}{2 \cdot 1}

r = \frac{- 4 + 4}{2 \cdot 1} : 0

r = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

r = 0, r = - 4

- 4 m + 2 = 7 m - 64

\frac{1}{4} + \frac{2}{7}

\frac{8 x y ^{3}}{- 4 x y ^{2}}

(x^{2})^{- 3}

∣ 3 c + 4 ∣ > 7

What are the solutions to the equation r^2+4r=0 ?
The solutions to the equation r^2+4r=0 are r=0,r=-4
Find the zeros of r^2+4r=0
The zeros of r^2+4r=0 are r=0,r=-4