What are the solutions to the equation 3x^2+20x-7=0 ?

The solutions to the equation 3x^2+20x-7=0 are x= 1/3 ,x=-7

Find the zeros of 3x^2+20x-7=0

The zeros of 3x^2+20x-7=0 are x= 1/3 ,x=-7

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3 x^{2} + 20 x - 7 = 0

x = \frac{1}{3}, x = - 7

Decimal Notation

x = 0.33333 \dots, x = - 7

Solution steps

3 x^{2} + 20 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

2 0^{2} - 4 \cdot 3 (- 7) = 22

x_{1, 2} = \frac{- 20 \pm 22}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 20 + 22}{2 \cdot 3}, x_{2} = \frac{- 20 - 22}{2 \cdot 3}

x = \frac{- 20 + 22}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 20 - 22}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 7

x^{2} - 10 x + 10 = 0

x^{2} + 62 = - 16 x

0.3 x^{2} + 0.21 x - 0.78 = 0

x^{2} + 8 x = 16

5 x^{2} + 6 x - 8

What are the solutions to the equation 3x^2+20x-7=0 ?
The solutions to the equation 3x^2+20x-7=0 are x= 1/3 ,x=-7
Find the zeros of 3x^2+20x-7=0
The zeros of 3x^2+20x-7=0 are x= 1/3 ,x=-7