What are the solutions to the equation 0=-x^2+2x+3 ?

The solutions to the equation 0=-x^2+2x+3 are x=-1,x=3

Find the zeros of 0=-x^2+2x+3

The zeros of 0=-x^2+2x+3 are x=-1,x=3

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0 = - x^{2} + 2 x + 3

x = - 1, x = 3

Solution steps

0 = - x^{2} + 2 x + 3

Switch sides

- x^{2} + 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 3 = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 ( - 1 )}, x_{2} = \frac{- 2 - 4}{2 ( - 1 )}

x = \frac{- 2 + 4}{2 ( - 1 )} : - 1

x = \frac{- 2 - 4}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = - 1, x = 3

9 x^{2} + 17 x - 2

4 (2 x - 1) = - 10 (x - 5)

n^{2} + 7 n + 10

2 x < 2

\frac{n}{4} \leq 3

What are the solutions to the equation 0=-x^2+2x+3 ?
The solutions to the equation 0=-x^2+2x+3 are x=-1,x=3
Find the zeros of 0=-x^2+2x+3
The zeros of 0=-x^2+2x+3 are x=-1,x=3